Practicing Success
If $7 x+11 y=1$ and $8 x+13 y=2$, then the value of $x$ and $y$ are: |
$-5,3$ $7,2$ $-3,2$ $-3,5$ |
$-3,2$ |
7x + 11y = 1....... (1) 8x + 13y = 2 ....... (2) Multiplying Equation (1) and Equation (2) by 8 and 7 resepectively, we have 56x + 88y = 8 and 56x + 91y = 14 Subtracting the second equation from the first, we get -3y = -6, y = 2 Now put the value of y in either 1 or 2 We are putting in 1 7x + 11y = 1 7x = -21 X = -3 |