Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

On doping germanium with donor atoms of density $10^{17} cm^{-3}$ its conductivity in mho/cm will be

[Given : $μ_e = 3800cm^2/ V−s$ and $n_i=2.5×10^{13}cm^{−13}$]

Options:

30.4

60.8

91.2

121.6

Correct Answer:

60.8

Explanation:

Conductivity $σ=n_ieμ_e=10^{17}×(1.6×10^{-19})×3800=60.8mho/cm$