Let functions $f:\{1,3,4\} →\{1,2,5\}$ and $g:\{1,2,5\} → \{1,3\}$ be defined as $f=\{(1,2),(3,5),(4,1)\}$ and $g = \{(1,3),(2,3),(5,1)\}$ respectively. Then, which one of the following is correct statement for gof? |
gof is one-one gof is onto gof is both one-one and onto gof is not defined |
gof is onto |
The correct answer is Option (2) → gof is onto $gof(x)=g(f(x))$ so $g(f(1))=g(2)=3$ $g(f(3))=g(5)=1$ $g(f(4))=g(1)=3$ ⇒ for every x ∈ co-domain there exists atleast some y ∈ domain ⇒ $gof$ is ONTO as $gof(1)=gof(4)$ ⇒ Not One one |