Practicing Success
Practicing Success
CUET Preparation Today
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Energy required to remove an electron from He+ ion is $\Delta E_1 = 54.4eV$ Energy required to remove an electron from He+ ion is $\Delta E_2 = \frac{54.4 eV}{2.2} = 24.6eV$ $\Delta E = \Delta E_1 + \Delta E_2 = 54.4 eV + 24.6 eV = 79 eV$ |
