The ratio of areas of two circles is 81 : 121. What will be the ratio of their circumferences ? |
9 : 11 121 : 81 11 : 9 81 : 121 |
9 : 11 |
Area of circle = \(\Pi \)\( {r }^{2 } \) Circumference of a circle = 2\(\Pi \)r ⇒ Ratio of circles A and B = 81 : 121 ⇒ \(\Pi \)\( {r }^{2 } \)A = 81, \(\Pi \)\( {r }^{2 } \)B = 121 ⇒ \(\Pi \)r A= 9, \(\Pi \)r B = 11. ⇒ Circumference ratio = 2\(\Pi \)9 : 2\(\Pi \)11 ⇒ 9 : 11. |