Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

The demand for a certain product is represented by the function $p = 300 +25x-x^2$ (in rupees), where $x$ is the number of units demanded and $p$ is the price per unit, then the marginal revenue when 15 units are sold,is

Options:

₹675

₹375

₹1050

₹3775

Correct Answer:

₹375

Explanation:

The correct answer is Option (2) → ₹375 **

The price function is $p = 300 + 25x - x^{2}$.

Revenue: $R = px = x(300 + 25x - x^{2})$

$R = 300x + 25x^{2} - x^{3}$

Marginal revenue: $R' = \frac{dR}{dx} = 300 + 50x - 3x^{2}$

At $x = 15$:

$R'(15) = 300 + 50(15) - 3(15^{2})$

$= 300 + 750 - 3(225)$

$= 1050 - 675$

$= 375$

The marginal revenue when 15 units are sold is ₹375.