Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

If OA is equally inclined to OX, OY, OZ and if A is $\sqrt{3}$ units from the origin, then the coordinates of A are

Options:

(3, 3, 3)

(-1, 1, -1)

(-1, 1, 1)

(1, 1, 1)

Correct Answer:

(1, 1, 1)

Explanation:

We have,

$l = m = n = \frac{1}{\sqrt{3}}$

$∴ \vec{OA}= |\vec{OA}| (l\hat{i}+m\hat{j}+n\hat{k})$

$⇒\vec{OA}= \sqrt{3}\left(\frac{1}{\sqrt{3}}\hat{i}+\frac{1}{\sqrt{3}}\hat{j}+\frac{1}{\sqrt{3}}\hat{k}\right)= \hat{i}=\hat{j}+\hat{k}$

So, coordinates of A are (1, 1, 1)