If OA is equally inclined to OX, OY, OZ and if A is $\sqrt{3}$ units from the origin, then the coordinates of A are
Answer & explanation
Correct answer: option 4
We have,
$l = m = n = \frac{1}{\sqrt{3}}$
$∴ \vec{OA}= |\vec{OA}| (l\hat{i}+m\hat{j}+n\hat{k})$
$⇒\vec{OA}= \sqrt{3}\left(\frac{1}{\sqrt{3}}\hat{i}+\frac{1}{\sqrt{3}}\hat{j}+\frac{1}{\sqrt{3}}\hat{k}\right)= \hat{i}=\hat{j}+\hat{k}$
So, coordinates of A are (1, 1, 1)