If maximum value of $f(x) = 2x^3 + 3x^2 - 6ax + 10$ occurs at $x = -3$, then the value of $a$ is _____. |
1 5 6 3 |
6 |
The correct answer is Option (3) → 6 ** Given function: $f(x)=2x^{3}+3x^{2}-6ax+10$ Maximum occurs at $x=-3$. At a maximum, $f'(x)=0$. Compute derivative: $f'(x)=6x^{2}+6x-6a$ Set $f'(-3)=0$: $6(-3)^{2}+6(-3)-6a=0$ $6(9)-18-6a=0$ $54-18-6a=0$ $36-6a=0$ $6a=36$ $a=6$ Answer: 6 |