If a rectangular sheet of paper of length 6 cm and width 3 cm is rolled to form a cylinder with height equal to the width of the paper, then what is the base radius of the cylinder (in cm)?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\frac{3}{\pi}\)
The height of the cylinder is the 3 cm width, so the sheet is rolled along its length: the 6 cm length goes round the circle and becomes the circumference of the base, \(2\pi r\).
Circumference (the 6 cm length): \(2\pi r=6\)
\(\displaystyle r=\frac{6}{2\pi}=\frac{3}{\pi}\) cm