If a rectangular sheet of paper of length 6 cm and width 3 cm is rolled to form a cylinder with height equal to the width of the paper, then what is the base radius of the cylinder (in cm)?

$\frac{6}{π}$ $\frac{3}{π}$ $\frac{3}{2π}$ $\frac{9}{2π}$

$\frac{3}{π}$

The circumference of the cylinder = 2πr According to the question, 2πr = 6 r = \(\frac{3}{π}\)