If a rectangular sheet of paper of length 6 cm and width 3 cm is rolled to form a cylinder with height equal to the width of the paper, then what is the base radius of the cylinder (in cm)? |
$\frac{6}{π}$ $\frac{3}{π}$ $\frac{3}{2π}$ $\frac{9}{2π}$ |
$\frac{3}{π}$ |
The circumference of the cylinder = 2πr According to the question, 2πr = 6 r = \(\frac{3}{π}\) |