If $f : R - \left\{\frac{3}{5}\right\} \to R$ be defined by $f(x) = \frac{3x + 2}{5x - 3}$, then
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $f^{-1}(x) = f(x)$ ##
Given that, $f(x) = \frac{3x + 2}{5x - 3}$
Let $y = \frac{3x + 2}{5x - 3}$
$3x + 2 = 5xy - 3y \Rightarrow x(3 - 5y) = -3y - 2$
$x = \frac{3y + 2}{5y - 3} \Rightarrow f^{-1}(x) = \frac{3x + 2}{5x - 3}$
$∴f^{-1}(x) = f(x)$