Functions $f, g : R \to R$ are defined, respectively, by $f(x) = x^2 + 3x + 1$, $g(x) = 2x - 3$, find $gog$.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $4x - 9$ ##
Given that, $f(x) = x^2 + 3x + 1, g(x) = 2x - 3$
$g og(x) = g\{g(x)\} = g(2x - 3)$
$= 2(2x - 3) – 3$
$= 4x - 6 - 3 = 4x – 9$