Functions $f, g : R \to R$ are defined, respectively, by $f(x) = x^2 + 3x + 1$, $g(x) = 2x - 3$, find $gog$. |
$4x - 6$ $4x - 9$ $2x - 6$ $4x^2 - 12x + 9$ |
$4x - 9$ |
The correct answer is Option (2) → $4x - 9$ ## Given that, $f(x) = x^2 + 3x + 1, g(x) = 2x - 3$ $g og(x) = g\{g(x)\} = g(2x - 3)$ $= 2(2x - 3) – 3$ $= 4x - 6 - 3 = 4x – 9$ |