A galvanometer of 60Ω resistance shows full scale deflection for a current of 8 mA. The shunt required to convert the galvanometer into an ammeter of range 0 to 6 A will be:

$4.67 × 10^{-2}Ω$ $5.67 × 10^{-2}Ω$ $2.67×10^{-2}Ω$ $8 × 10^{-2}Ω$

$8 × 10^{-2}Ω$

The correct answer is Option (4) → $8 × 10^{-2}Ω$