The direction ratios of the line (1-x)/3=(7y-14)/2=(z-3)/2 are

\(=\frac{1-x}{3}=\frac{7y-14}{2}=\frac{z-3}{2}\)

\(\frac{-(x+1}{3}=\frac{(y-2)}{2}=\frac{z-3}{2}⇒\frac{z-1}{-3}=\frac{y-2}{\frac{2}{7}}=\frac{z-3}{2}\)

Direction ratio are 

x = -3

y = $\frac{2}{7}$

z = 2

So direction ratios are = (-3, $\frac{2}{7}$, 2) or $\frac{-3×7,2,2×7}{7}$

$=\frac{-21,2,14}{7}=(-21,2,14)$ taking same L.C.M

So option 4 is correct.