Practicing Success
Practicing Success
CUET Preparation Today
If sec θ = $\frac{65}{63}$ and θ is an acute angle, then the value of 8(cosecθ - cot θ) is : |
1 4 2 8 |
1 |
sec θ = \(\frac{65}{63}\) { we know, sec θ = \(\frac{H}{B}\) ] By using pythagoras theorem, P² + B² = H² P² + 63² = 65² P = 16 Now, 8(cosecθ - cot θ) = 8 ( \(\frac{65}{16}\) - \(\frac{63}{16}\) ) = 8 ( \(\frac{2}{16}\) ) = 1
|
