Read the information given below carefully and answer the question that follows: (A) The mean of 20 observations is 17. On checking, it was found that two observations were wrongly copied as 3 and 6. If the wrong observations are replaced by correct values 8 and 9, then the correct mean will be 16.4. Choose the correct option: |
(A), (B), (C) and (D) are all correct (A) and (B) are incorrect but (C) and (D) are correct (A), (B), (C) and (D) are all incorrect (A) is incorrect but (B), (C) and (D) are correct |
(A) is incorrect but (B), (C) and (D) are correct |
The correct answer is Option (4) → (A) is incorrect but (B), (C) and (D) are correct (A) Mean of 20 observations = 17 Wrongly copied values = 3 and 6 Correction in total: (8+9)−(3+6) = 17−9 = 8 New total = 340+8=348 Correct mean:348/20 = 17.4 . hence, statement A is incorrect. (B) = $4^{3.5} : 2^5$ $4^{3.5}$ =$(2^2)^{3.5}$ = $2^7$ So ratio: $2^7$ :$2^5$ = $2^2$:1 = 4: 1 Statement (B) is correct (C) 1.5 : 2.5= 15/10 : 25/10 = 15 : 25 = 3 : 5 Statement (C) is correct (D) 2A=3B=4C Let common value = k A= k/2, B =k/3 and C = k/4 A:B:C = 1/2 : 1/3 : 1/4 = 6 : 4 : 3 Statement (D) is correct
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