CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below : | ||||||||||||||||||||
(A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) (A)-(IV), (B)-(II), (C)-(III), (D)-(I) |
(A)-(IV), (B)-(III), (C)-(II), (D)-(I) |
The correct answer is option (2) → (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (A) $|A^T|=|A|$ (IV) (B) $A(adj\,A)=(adj\,A)A$ (III) (C) $A^{-1}|A|=(adj\,A)$ as $A\,adj\,A=I|A|$ pre multiplying with $A^{-1}$ $adj\,A=A^{-1}|A|$ (II) (D) $(AB)^{-1}=B^{-1}A^{-1}$ (I) |
