Practicing Success
The function $f(x)=|x-1|$ is |
Continuous at x=1 and not differentiable at x=1. Continuous and differentiable at x=1. Discontinuous and differentiable at x=1. Neither continuous nor differentiable at x=1. |
Continuous at x=1 and not differentiable at x=1. |
The correct answer is Option (1) → Continuous at x=1 and not differentiable at x=1. $f(x)=|x-1|=\left\{\begin{matrix}x-1&x≥1\\1-x&x<1\end{matrix}\right.$ $\underset{x→1^+}{\lim}f(x)=0=\underset{x→1^-}{\lim}f(x)=f(1)$ f(x) is continuous at x = 1 $f'(x)=\left\{\begin{matrix}1&x≥1\\-1&x<1\end{matrix}\right.$ (LHD ≠ RHD) at x = 1 ⇒ Not differentiable at x = 1 |