Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

The value of $\frac{(0.1×0.1 × 0.1 +0.02 × 0.02 × 0.02)}{(0.2×0.2×0.2+0.04 × 0.04 × 0.04)}$ is:

Options:

0.0125

0.125

0.25

0.5

Correct Answer:

0.125

Explanation:

The correct answer is Option (2) → 0.125

$\frac{(0.1×0.1 × 0.1 +0.02 × 0.02 × 0.02)}{(0.2×0.2×0.2+0.04 × 0.04 × 0.04)}$

⇒\(\frac{0.1^3 + 0.02^3}{0.2^3 + 0.04^3}\)

\(\frac{0.1^3 + 0.02^3}{2^3(0.1^3 + 0.02^3)}\)

\(\frac{1}{8}\) = 0.125 Answer