An unbiased die is thrown. The probability of getting a multiple of 2 is :

$\frac{1}{2}$

Number appears on dice = 1 , 2 , 3 , 4 , 5 , 6

Total number of outcomes = 6

Numbers multiple of 2 = 2 , 4 and 6

Number of Possible outcomes = 3

Probability of getting a multiple of 2 is = \(\frac{3}{6}\)

= \(\frac{1}{2}\)

The correct answer is option (3) : $\frac{1}{2}$