If A and B are square matrices of the same order, then the value of $(A+B)(A-B)$ is equal to: |
$A^2-B^2$ $A^2-B A-A B-B^2$ $A^2-B^2+B A-A B$ $A^2-B A+B^2+A B$ |
$A^2-B^2+B A-A B$ |
The correct answer is Option (3) → $A^2-B^2+B A-A B$ $(A+B)(A-B)=A(A-B)+B(A-B)$ $=A^2-AB+BA-B^2$ $=A^2-B^2+BA-AB$ The value is $A^2 - B^2 + BA - AB$. |