If A and B are square matrices of the same order, then the value of $(A+B)(A-B)$ is equal to:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $A^2-B^2+B A-A B$
$(A+B)(A-B)=A(A-B)+B(A-B)$
$=A^2-AB+BA-B^2$
$=A^2-B^2+BA-AB$
The value is $A^2 - B^2 + BA - AB$.