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If $\begin{vmatrix}3 & x\\x & 1\end{vmatrix}=\begin{vmatrix}3 & 2\\4 & 1\end{vmatrix},$ then x is equal to : |
$2\sqrt{2}$ $-2\sqrt{2}$ $±2\sqrt{2}$ 0 |
$±2\sqrt{2}$ |
The correct answer is Option (3) → $±2\sqrt{2}$ $\begin{vmatrix}3&x\\x&1\end{vmatrix}=\begin{vmatrix}3&2\\4&1\end{vmatrix}$ $⇒3-x^2=3-8$ $x^2=8⇒x=±2\sqrt{2}$ |
