The plane $2x-(1+\lambda ) y + 2\lambda z =0, \lambda \in R$ passes through the intersection of planes :

$2x-y = 0 $ and $y-3z=0$

The correct answer is Option (1) → $2x-y = 0 $ and $y-3z=0$

$2x-(1+λ) y + 2λz =0$ is of the from $P_1+λP_2$

$\underbrace{2x-y}_{P_1}+λ\underbrace{-y+2z}_{P_2}=0$

it passes through $P_1:2x-y=0$ and $P_2:-y+2z=0$