Practicing Success
Practicing Success
CUET Preparation Today
The differentiation of $\frac{x^3}{1-x^3}$ w.r.t. $x^3$ is : |
$\frac{2}{(1-x^3)^2}$ $\frac{1}{(1-x^3)^2}$ $\frac{-1}{(1-x^3)^2}$ $\frac{1}{1-x^3}$ |
$\frac{1}{(1-x^3)^2}$ |
The correct answer is Option (2) → $\frac{1}{(1-x^3)^2}$ $y=\frac{x^3}{1-x^3}$ $z=x^3$ $\frac{dy}{dx}=\frac{3x^2(1-x^3)}{(1-x^3)^2}+3x^2(x^3)$ $=\frac{3x^2}{(1-x^3)^2}$ $\frac{dz}{dx}=3x^2$ so $\frac{dy}{dz}=\frac{1}{(1-x^3)^2}$ |
