A lens is formed by placing the plane faces of two identical plano-convex lenses (each of focal length 40 cm) touching each other. It is used to obtain a real, inverted image of the same size as the object. The distance of the object from the lens is: |
20 cm 40 cm 80 cm 160 cm |
40 cm |
The correct answer is Option (2) → 40 cm When two lenses are kept in contact, the effective focal length $(F_{eff})$ is - $(F_{eff})=\frac{1}{F_1}+\frac{1}{F_2}$ $(F_{eff})=\frac{1}{40}+\frac{1}{40}=\frac{2}{40}=\frac{1}{20}$ $(F_{eff})=20cm$ [Both lens had $f = 40 cm$ and identically] Now, Since, $v=-u$ a image should be inverted and be of the same size. $(F_{eff})=\frac{1}{u}-\frac{-1}{u}$ $\frac{1}{20}=\frac{2}{u}$ $=u=40cm$ |