Practicing Success
A body is moved along a straight line by a machine delivering a constant power. The distance moved by the body in time t is proportional to : |
\(t^{3/4}\) \(t^{1/2}\) \(t^{2}\) \(t^{3/2}\) |
\(t^{3/2}\) |
Let us assume that the displacement of the body is directly proportional to \(t^n\), i.e. : \(s = Kt^n\) Thus, the velocity : \(v = \frac{ds}{dt} = Kn t^{n-1}\) and the acceleration : \(a = \frac{dv}{dt} = Kn(n-1)t^{n-2}\) The Force : \(F = ma = mKn(n-1)t^{n-2}\) Hence, Power : \(P = Fv = (mKn(n-1)t^{n-2})(Kn t^{n-1})\) \(P = mKn^2(n-1)t^{2n-3}\) As power is constant, Thus, independent of time. Hence : 2n - 3 = 0 \(\Rightarrow n = \frac{3}{2}\) Thus, \(s \propto t^{3/2}\)
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