Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The dimensions of universal gravitational constant are

Options:

$[M^{-1}L^3T^{-2}]$

$[ML^2T^{-1}]$

$[M^{-2}L^3T^{-2}]$

$[M^{-2}L^2T^{-1}]$

Correct Answer:

$[M^{-1}L^3T^{-2}]$

Explanation:

F = G$\frac{m_1m_2}{2^2}$

[G] = $\frac{Fr^2}{m_1m_2}$ = $\frac{[MLT^{-2}][L^2]}{[M^2]}$ = $[M^{-1}L^3T^{-2}]$