Practicing Success
Match List-I with List -II.
Choose the correct answer from he options given below : |
(A)-(II),(B)-(I),(C)-(IV),(D)-(III) (A)-(III),(B)-(I),(C)-(II),(D)-(IV) (A)-(IV),(B)-(I),(C)-(III),(D)-(II) (A)-(III),(B)-(IV),(C)-(II),(D)-(I) |
(A)-(III),(B)-(IV),(C)-(II),(D)-(I) |
The correct answer is Option (4) → (A)-(III),(B)-(IV),(C)-(II),(D)-(I) (A) $(\hat{i}×\hat{k}).\hat{j}+(\hat{j}×\hat{k}).\hat{i}$ $=-\hat j.\hat j+\hat i.\hat i=-1+1=0$ (III) (B) $\hat{i}.(\hat{j}×\hat{k})+\hat{j}.(\hat{i}×\hat{k})+\hat{k}.(\hat{i}×\hat{j})$ $=\hat i.\hat i+\hat j.-\hat j+\hat k.\hat k=1-1+1=1$ (IV) (C) $(\hat{k}×\hat{j}).\hat{i}+\hat{k}.\hat{j}=-\hat i.\hat i+1=-1$ (II) (D) $\hat{k}.(\hat{i}×\hat{j})+(\hat{j}×\hat{k}).\hat{i}$ $=\hat k.\hat k+\hat j.\hat j=1+1=2$ (I) |