The value of $\underset{x→∞}{\lim}(\frac{3x-4}{3x+2})^{\frac{x+1}{3}}$ is

$e^{-2/3}$ $e^{-1/3}$ $e^{-2}$ none of these

$e^{-2/3}$

$\underset{x→∞}{\lim}(1-\frac{6}{3x+2})^{\frac{x+1}{3}}$ $⇒e^{\underset{x→∞}{\lim}(\frac{-6}{3x+2})(\frac{x+1}{3})}⇒e^{\underset{x→∞}{\lim}\frac{-2(1+1/x)}{(3+2/x)}}=e^{-2/3}$