If a charge spherical conductor of radius 10 cm has potential V at a point distance 5 cm. from its center, then the potential at a point distance 15 cm from the centre will be

$\frac{V}{3}$ $\frac{2V}{3}$ $\frac{3V}{2}$ $3V$

$\frac{2V}{3}$

$ V = \frac{kQ}{10}$ $ V'= \frac{kQ}{15} = \frac {2V}{3}$