If $ x + \frac{1}{x} = 7$, find the value of $ x^3 +\frac{1}{x^3}$.

343 322 340 332

322

If $ x + \frac{1}{x} = 7$, find the value of $ x^3 +\frac{1}{x^3}$ If x + \(\frac{1}{x}\)  = n then, $x^3 +\frac{1}{x^3}$ = n3 - 3n $ x + \frac{1}{x} = 7$, $ x^3 +\frac{1}{x^3}$ = 73 - 3 × 7 = 322