If $ x + \frac{1}{x} = 7$, find the value of $ x^3 +\frac{1}{x^3}$.
Answer & explanation
Correct answer: option 2
If $ x + \frac{1}{x} = 7$,
find the value of $ x^3 +\frac{1}{x^3}$
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3n
$ x + \frac{1}{x} = 7$,
$ x^3 +\frac{1}{x^3}$ = 73 - 3 × 7 = 322