Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

In a test, a student got 39% marks and passed by 12 marks. In the same test another student got 27% of the marks and got 25% less than the essential passing marks. What are the maximum pass marks?

Options:

152

144

156

142

Correct Answer:

144

Explanation:

Passing marks = (39% - 12)

27% of total = \(\frac{3}{4}\) (39% - 12)

108% × x = 117% - 36

9% × x = 36

        x = 400

Passing marks = \(\frac{400 x 39}{100}\)

                     = 144