Practicing Success
If $f: R→R$ is a function given by $f(x)= [x]$ (greatest integer function), then which of the following is/are correct. A. $f$ is one-one B. $f$ is onto C. Range of $f$ is I (set of the integers) D. $f(2.5)=2$ E. $f$ is bijective Choose the correct answer from the options given below: |
C, E only B, C, D only A, B only C, D only |
C, D only |
$f: R→R$ $f(x)=[x]$ (Greatest integer function) $[x]$ = the greatest integer $≤x$ for the function to be one-one $f_1=f_2⇒x_1=x_2$ but this is not the case eg: for $x = 2.2,x=2.3,x=2.4$ $f(2.2)=2,f(2.3)=2,f(2.4)=2$ so, all the value of $x$ are different but for these values, value of f(x) is same. ⇒ this clearly says that function is not one-one. for function be onto, all the values in codomain must have atleast one preimage in domain codomain is R (set of real numbers) for numbers like $3.5, 4.7$ (Non integral numbers) if $f(x) = 3.5$ or $f(x) = 4.7$ This is impossible for any value of $x$ as the range consist of only integer values. So, function is not ONTO as function is not onto as well as not one-one it is NOT bijective so, (A, B, E) → are incorrect The range of $f$ is $I$ (set of the integers) $f(2.5)=2$ (as the greatest integer value less than or equal to 2.5 is 2) So, only C, D are correct. |