If $x +\frac{1}{x}=\sqrt{3}$, then the value of $x^{18} + x^{12} + x^6 + 1$ is:

0 2 1 3

0

If $x +\frac{1}{x}=\sqrt{3}$, then the value of $x^{18} + x^{12} + x^6 + 1$ If $x +\frac{1}{x}=\sqrt{3}$, then the value of x6 = -1 (always) Put this value in required equation, $x^{18} + x^{12} + x^6 + 1$ = (x6)3 + (x6)2 + x6 + 1 = -1 + 1 -1 + 1 = 0