Identify the following function $f(x)=\log(\frac{1-x}{1+x})$ as
Answer & explanation
Correct answer: option 1
$f(-x)=\log\{\frac{1-(-x)}{1+(-x)}\}$
$=\log(\frac{1+x}{1-x})$
$=-f(x)$
Hence, f(x) is odd.
Identify the following function $f(x)=\log(\frac{1-x}{1+x})$ as
Correct answer: option 1
$f(-x)=\log\{\frac{1-(-x)}{1+(-x)}\}$
$=\log(\frac{1+x}{1-x})$
$=-f(x)$
Hence, f(x) is odd.