Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

Identify the following function $f(x)=\log(\frac{1-x}{1+x})$ as

Options:

Odd

Even

Neither Odd nor Even

Cannot be determined

Correct Answer:

Odd

Explanation:

$f(-x)=\log\{\frac{1-(-x)}{1+(-x)}\}$

$=\log(\frac{1+x}{1-x})$

$=-f(x)$

Hence, f(x) is odd.