12 years ago, A’s mother was four times as old as A. After 14 years she will be twice as old as A. Find the present age of A.
Answer & explanation
Correct answer: option 2
Let the age of mother 12 years ago = 4R ,
Then age of A 12 years ag0 = 1R
Age of mother after 14 years = 4R + 12 + 14 = 4R + 26
Age of A after 14 years = 1R + 26
ATQ,
⇒ \(\frac{4R\;+\;26}{1R\;+\;26}\) = \(\frac{2}{1}\)
⇒ 4R + 26 = 2R + 52
⇒ 2R = 26
⇒ 1R = 13
Age of A at present = 13 + 12 = 25 years