Practicing Success
Practicing Success
CUET Preparation Today
If $y=\frac{1}{2}x\sqrt{a^2-x^2}+\frac{a^2}{2}sin^{-1}\frac{x}{a},$ then $\frac{dy}{dx}=$ |
$\sqrt{a^2-x^2}$ $\sqrt{a^2+x^2}$ $\frac{1}{\sqrt{a^2-x^2}}$ $\frac{1}{\sqrt{a^2+x^2}}$ |
$\sqrt{a^2-x^2}$ |
