Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity '. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity:

Options:

\(\frac{\omega M}{M+2m}\)

\(\frac{\omega (M+2m)}{M}\)

\(\frac{\omega m}{M+2m}\)

\(\frac{\omega (M-2m)}{M+2m}\)

Correct Answer:

\(\frac{\omega M}{M+2m}\)

Explanation:

Since, no external torque is applied, angular momentum is constant.

\(I_1\omega_1 = I_2\omega_2\)

\(I_1 = MR^2 ; I_2 = MR^2 + 2mR^2\)

\(\omega_2 = \frac{I_1}{I_2}\omega = \frac{M}{M+2m}\omega\)