Let $f(x)=x^3$ be a function with domain

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

Let $f(x)=x^3$ be a function with domain $\{0,1,2,3\}$ then domain of $f^{-1}$ is :

Options:

$\{3,2,1,0\}$

$\{0,-1,-2,-3\}$

$\{0,1,8,27\}$

$\{0,-1,-8,-27\}$

Correct Answer:

$\{0,1,8,27\}$

Explanation:

f(x) = x³

domain = {0, 1, 2, 3}

so range = ?

checking for each value of domain

f(0) = 0³ = 0

f(1) = 1³ = 1

f(2) = 2³ = 8

f(3) = 3³ = 27

range = {0, 1, 8, 27}

for f(x)

for f^-1(x)

Domain (f^-1(x)) = {0, 1, 8, 27}