If $ X^4 +\frac{16}{x^4}= 15617, x > 0$, then find the value of $ X +\frac{2}{x}$
Answer & explanation
Correct answer: option 2
$ X^4 +\frac{16}{x^4}= 15617, x > 0$
If x4 + \(\frac{1}{x^4}\) = a
then x2 + \(\frac{1}{x^2}\) = \(\sqrt {a + 2}\) = b
and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
x2 + \(\frac{4}{x^2}\) = \(\sqrt {15617 + 2 × 4}\) =125
x + \(\frac{2}{x}\) = \(\sqrt {125 + 2 × 2}\) = \(\sqrt {129}\)