Practicing Success
In a circle, AB and CD are two diameters which are perpendicular to each other. Find the length of chord AC. |
$\sqrt{2}$ CD $\frac{AB}{\sqrt{2}}$ $\frac{CD}{2}$ 2AB |
$\frac{AB}{\sqrt{2}}$ |
In triangle AOC , h² = b² + p² AC² = OA² + OC² { OA = OC = Radius of circle } AC² = OA² + OA² AC² = 2OA² AC² = 2 × (\(\frac{AB}{2}\))² AC² = \(\frac{AB²}{2}\) AC = \(\frac{AB}{√2}\)
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