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For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is |
6 mA 4.8 mA 24 mA 8 mA |
4.8 mA |
Given that, $β = 0.8$ $ΔI_b = 6 mA$ $ΔI_c = βΔI_b$ $∴ΔI_c = 0.8 × 6 mA = 4.8 mA$ |
