For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA is
Answer & explanation
Correct answer: option 2
Given that,
$β = 0.8$
$ΔI_b = 6 mA$
$ΔI_c = βΔI_b$
$∴ΔI_c = 0.8 × 6 mA = 4.8 mA$