Two tangents AP and AQ are drawn to a circle with center O from an external point A, where P and Q are points on the circle. If ∠PAQ = 80°, then ∠AOP is equal to?
Answer & explanation
Correct answer: option 4
∠PAQ = 80°, and
∠P and ∠Q = 90°
In the case of tangent ⇒ line OA bisect the angles ∠PAQ and ∠POQ.
Therefore,
In Δ PAO:
∠P = 90°, ∠PAO = 40°, so ∠PAO = 90° - 40° = 50°