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If the solution of the differential equation $\frac{dy}{dx}=\frac{ax+3}{2y+f}$ represents a circle, then the value of ‘a’ is: |
2 -2 3 -3 |
-2 |
$(ax+3)dx=(2y+f)dy⇒\frac{-a}{2}x^2+y^2-3x+fy+c=0$ This will represent a circle, if $\frac{-a}{2}=1⇒a=-2$ |
