Two concentric circles are of radii 15 cm and 6 cm. Whatis the length (in cm) of the chord ofthe larger circle that is tangent to the smaller circle? |
$6\sqrt{21}$ $9\sqrt{21}$ $3\sqrt{21}$ $4\sqrt{21}$ |
$6\sqrt{21}$ |
We have, AO = 15 cm and OC = 6 cm According to the Pythagoras theorem, AC2 = AO2 - OC2 = AC2 = 152 - 62 = AC2 = 225 - 36 = AC2 = 189 = AC = $3\sqrt{21}$ AB = 2AC = 2 x $3\sqrt{21}$ = $6\sqrt{21}$ cm |