The correct answer is Option (1) → Co
Step 1: Recall the principle
- Metals react with acids to liberate hydrogen if they are more electropositive than H⁺, i.e., if they can be oxidized by H⁺:
$M^{2+} + 2H^+ → M^{3+} + H_2$
- Compare standard potentials:
- H⁺/H₂ → 0 V
- Metal M²⁺/M³⁺: If $E^\circ > 0$, metal is less likely to be oxidized, i.e., will not liberate H₂.
- If $E^\circ < 0$, metal is more easily oxidized → reacts with acids → liberates H₂.
Step 2: Examine the given potentials
|
Metal
|
$E^\circ(M^{3+}/M^{2+})$
|
|
V
|
–0.26
|
|
Ti
|
–0.37
|
|
Co
|
+1.97
|
|
Cr
|
–0.41
|
- Co: +1.97 → very positive → does not react with acids
- V, Ti, Cr → negative → will react → liberate H₂
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