Based on the data given below, which metal in its +2 oxidation state will not librate hydrogen from acids?
|
Metal |
V |
Ti |
Co |
Cr |
|
$E° (M^{3+}/M^{2+}$) |
-0.26 |
-0.37 |
+1.97 |
-0.41 |
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Co
Step 1: Recall the principle
- Metals react with acids to liberate hydrogen if they are more electropositive than H⁺, i.e., if they can be oxidized by H⁺:
$M^{2+} + 2H^+ → M^{3+} + H_2$
- Compare standard potentials:
- H⁺/H₂ → 0 V
- Metal M²⁺/M³⁺: If $E^\circ > 0$, metal is less likely to be oxidized, i.e., will not liberate H₂.
- If $E^\circ < 0$, metal is more easily oxidized → reacts with acids → liberates H₂.
Step 2: Examine the given potentials
|
Metal |
$E^\circ(M^{3+}/M^{2+})$ |
|
V |
–0.26 |
|
Ti |
–0.37 |
|
Co |
+1.97 |
|
Cr |
–0.41 |
- Co: +1.97 → very positive → does not react with acids
- V, Ti, Cr → negative → will react → liberate H₂