The distance of Neptune and Saturn from sun are nearly 1013 and 1012 meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio : |
√10 100 10√10 1 /√10 |
10√10 |
Kepler’s third law T2 ∝ R3 : \(\Rightarrow \frac{T_{Neptune}}{T_{Saturn}} = [\frac{R_{Neptune}}{R_{Saturn}}]^{3/2}\) = \([\frac{10^{13}}{10^{12}}]^{3/2}\) = \(10\sqrt{10}\) |