Three integers are selected simultaneously from the set of integers {1, 2, 3, 4, ….., 50}. The probability that the selected numbers are consecutive, is equal to

$\frac{3}{(25)(49)}$

Possible set of three consecutive numbers are {1, 2, 3}, {2, 3, 4}, {3, 4, 5},….{48, 49, 50}. which are 48 in number.

Thus, required probability = $\frac{{ }^{48} C_1}{{ }^{50} C_3}$

$=\frac{3}{(25)(49)}$