CUET Preparation Today
The value of the determinant $\left|\begin{array}{lll}a^2 & a & 1 \\ b^2 & b & 1 \\ c^2 & c & 1\end{array}\right|$ is: |
zero $a+b+c-3 a b c$ $(a-b)(b-c)(a-c)$ $a^2+b^2+c^2-a b c$ |
$(a-b)(b-c)(a-c)$ |
The correct answer is Option (3) → $(a-b)(b-c)(a-c)$ |
