If \(y = \sqrt{2024x+2025}\), then which of the following is correct?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \(y\displaystyle\frac{d^2y}{dx^2}+\left(\frac{dy}{dx}\right)^2=0\)
Squaring first removes the root, and then implicit differentiation is short:
\(y^2 = 2024x + 2025\)
Differentiating with respect to x:
\( \displaystyle 2y\frac{dy}{dx} = 2024 \)
Differentiating again, by the product rule:
\( \displaystyle 2\left(\frac{dy}{dx}\right)^2 + 2y\frac{d^2y}{dx^2} = 0 \)
\( \displaystyle y\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 = 0 \)