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The value of $4\left[\frac{(1 - \sec A)^{2} + (1 + \sec A)^{2}}{1 + \sec^{2}A}\right]$ is : |
4 1 2 8 |
8 |
4 [ \(\frac{ ( 1 - secA )² + ( 1 + secA )²}{ 1 + sec²A }\) ] = 4 [ \(\frac{ 1 + sec²A -2secA + 1 + sec²A + 2secA}{ 1 + sec²A }\) ] = 4 [ \(\frac{ 2+ 2sec²A }{ 1 + sec²A }\) ] = 8 |
